optimize oracle query - Tosska Technologies Limited

2023-02-162023-02-18

How to Tune SQL with IN Subquery with Intersect for Oracle?

Here is an example SQL that retrieves data from EMPLOYEE and DEPARTMENT table with the employee’s grade code in the GRADE table.

SELECT emp_id,
       emp_name,
       dpt_name
FROM   employee,
       department
WHERE  emp_dept = dpt_id
       AND emp_grade IN (SELECT grd_id
                         FROM grade
                         WHERE grd_min_salary < 200000)
and emp_dept < ‘D’

Here the following is the query plan of this SQL, it takes 8.3 seconds to finish. The query plan shows a Hash Join with GRADE and EMPLOYEE and then hash join to DEPARTMENT. It looks like Oracle gave up any Nested Loops operations after the actual number of rows is returned from the GRADE table in this adaptive plan.

In order to ask Oracle to consider the Nested Loops operations, I added an extra Intersect operation in the subquery to rapidly narrow down the result set of grd_id returned from the GRADE table first.

SELECT emp_id,
       emp_name,
       dpt_name
FROM   employee,
       department
WHERE  emp_dept = dpt_id
       AND emp_grade IN (SELECT grd_id
                         FROM   grade
                         WHERE  grd_min_salary < 200000                          INTERSECT SELECT e1.emp_grade
                                   FROM employee e1
                                   WHERE emp_dept < ‘D’)
       AND emp_dept < ‘D’

The rewritten SQL generates a query plan that is entirely different from the original query plan, The new plan is using “Nested Loops” from DEPARTMENT to EMPLOYEE as the first steps and then Hash Join to the GRADE table. The new plan now takes 0.81 seconds only.

This kind of rewrite can be achieved by Tosska SQL Tuning Expert Pro for Oracle automatically, it shows that the rewrite is more than 10 times faster than the original SQL.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2022-10-10

How to Tune SQL Statement with CASE Expression by Hints Injection for Oracle?

Here the following is a simple SQL statement with a CASE expression syntax.

SELECT *
FROM employee
WHERE
CASE
WHEN emp_salary< 1000
THEN ‘low’
WHEN emp_salary>100000
THEN ‘high’
ELSE ‘Normal’
END = ‘low’

Here the following are the query plans of this SQL, it takes 4.64 seconds to finish. The query shows a Full Table Scan of the EMPLOYEE table due to the CASE expression cannot utilize the emp_salary index. It is because the CASE statement disabled the index range search of the emp_salary index.

Commonly, we will try to enable index search by forcing the SQL with an Index hint as the following:

SELECT /*+ INDEX(@SEL$1 EMPLOYEE) */ *
FROM employee
WHERE CASE
WHEN emp_salary < 1000
THEN ‘low’
WHEN emp_salary > 100000
THEN ‘high’
ELSE ‘Normal’
END = ‘low’

Although the CASE statement disabled the index range search of the emp_salary index, an index full scan is now enabled to help filter the result more quickly compared with the original full table scan of the EMPLOYEE table.

This hint injection takes 0.38 seconds and it is 12 times faster than the original SQL will full table scan. For this kind of SQL statement that you cannot change your source code, you can use SQL Patch with the hints and SQL text deployed to the database without the need of changing your source code.

If you can modify your source code, the best performance will be to rewrite the CASE expression into the following syntax with multiple OR conditions.

SELECT *
FROM employee
WHERE emp_salary < 1000
AND ‘low’ = ‘low’
OR NOT ( emp_salary < 1000 )
  AND emp_salary > 100000
  AND ‘high’ = ‘low’
OR NOT ( emp_salary < 1000
  OR emp_salary > 100000 )
  AND ‘Normal’ = ‘low’

The new query plan shows an INDEX RANGE SCAN OF emp_salary index.

This kind of rewrite and hints injection can be achieved by Tosska SQL Tuning Expert Pro for Oracle automatically,

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2022-07-052022-07-05

How to use ROWID to improve an UPDATE statement for Oracle?

Here the following is an Update SQL with a subquery that updates the EMPLOYEE table if the emp_dept satisfies the records returned from a subquery.

update  employee
set  emp_name = ‘testing’
where  emp_dept IN (select dpt_id
from department
where dpt_name like ‘A%’)
and emp_grade>2000

You can see Oracle uses a Hash join of the DEPARTMENT table and EMPLOYEE table to execute the update process. This query plan takes 1.96 seconds to complete and no index is used even though emp_dept, dpt_id, and emp_grade are indexed columns. It looks like the most expansive operation is the Table Access Full scan of the EMPLOYEE table.

Let’s rewrite the SQL into the following syntax to eliminate EMPLOYEE’s Table Access Full operation from the query plan. The new subquery with the italic Bold text is used to force the EMPLOYEE to extract records with emp_dept in the DEPARTMENT table with the dpt_name like ‘A%’. The ROWID returned from the EMPLOYEE(subquery) is to make sure a more efficient table ROWID access to the outer EMPLOYEE table.

UPDATE  employee
SET emp_name=‘testing’
WHERE   ROWID IN (SELECT  ROWID
FROM employee
WHERE emp_dept IN (SELECT  dpt_id
FROM department
WHERE dpt_name LIKE‘A%’))
AND emp_grade > 2000

You can see the final query plan with this syntax has a better cost without full table access to the EMPLOYEE table. The new syntax takes 0.9 seconds and it is more than 2 times faster than the original syntax.

This kind of rewrite can be achieved by Tosska SQL Tuning Expert Pro for Oracle automatically, there is another SQL rewrite with similar performance, but it is not suitable to discuss in this short article, maybe I can discuss it later in my blog.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2022-04-19

How to index SQL with aggregate function SQL for Oracle?

Here the following is an example SQL shows you that select the maximum emp_address which is not indexed in the EMPLOYEE table with 3 million records, the emp_grade is an indexed column.

select max(emp_address) from employee a
where emp_grade<4000

As 80% of the EMPLOYEE table’s records will be retrieved to examine the maximum emp_address string. The query plan of this SQL shows a Table Access Full on EMPLOYEE table is reasonable.

How many ways to build an index to improve this SQL?
Although it is simple SQL, there are still 3 ways to build an index to improve this SQL, the following are the possible indexes that can be built for the SQL, the first one is a single column index and the 2 and 3 are the composite index with a different order.
1. EMP_ADDRESS
2. EMP_GRADE, EMP_ADDRESS
3. EMP_ADDRESS, EMP_GRADE

Most people may use the EMP_ADDRESS as the first choice to improve this SQL, let’s see what the query plan is if we build a virtual index for the EMP_ADDRESS column in the following, you can see the estimated cost is reduced by almost half, but this query plan is finally not being used after the physical index is built for benchmarking due to actual statistics is collected.

The following query shows the EMP_ADDRESS index is not used and the query plan is the same as the original SQL without any new index built.

Let’s try the second composite index (EMP_GRADE, EMP_ADDRESS), the new query plan shows an Index Fast Full Scan of this index, it is a reasonable plan which no table’s data is needed to retrieve. So, the execution time is reduced from 16.83 seconds to 3.89 seconds.

Let’s test the last composite index (EMP_ADDRESS, EMP_GRADE) that EMP_ADDRESS is placed as the first column in the composite index, it creates a new query plan that shows an extra FIRST ROW operation for the INDEX FULL SCAN (MIN/MAX), it highly reduces the execution time from 16.83 seconds to 0.08 seconds.

So, indexing sometimes is an art that needs you to pay more attention to it, some potential solutions may perform excess your expectation.

The best index solution is now more than 200 times better than the original SQL without index, this kind of index recommendation can be achieved by Tosska SQL Tuning Expert for Oracle automatically.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2022-01-172022-03-16

How is the order of the columns in a composite index affecting a subquery performance for Oracle?

We know the order of the columns in a composite index will determine the usage of the index or not against a table. A query will use a composite index only if the where clause of the query has at least the leading/left-most columns of the index in it. But, it is far more complicated in correlated subquery situations. Let’s have an example SQL to elaborate the details in the following.

SELECT D.*
FROM department D
WHERE EXISTS (SELECT    Count(*)
FROM    employee E
WHERE     E.emp_id < 1050000
AND E.emp_dept = D.dpt_id
GROUP BY E.emp_dept
HAVING    Count(*) > 124)

Here the following is the query plan of the SQL, it takes 10 seconds to finish. We can see that the SQL can utilize E.emp_id and E.emp_dept indexes individually.

Let’s see if a new composite index can help to improve the SQL’s performance or not, as a rule of thumb, a higher selectivity column E.emp_id will be set as the first column in a composite index (E.emp_id, E.emp_dept).

The following is the query plan of a new composite index (E.emp_id, E.emp_dept) and the result performance is not good, it takes 11.8 seconds and it is even worse than the original query plan.

If we change the order of the columns in the composite index to (E.emp_dept, E.emp_id), the following query plan is generated and the speed is improved to 0.31 seconds.

The above two query plans are similar, the only difference is the “2” operation. The first composite index with first column E.emp_id uses an INDEX RANGE SCAN of the new composite index, but the second query plan uses an INDEX SKIP SCAN for the first column of E.emp_dept composite index. You can see there is an extra filter operation for E.emp_dept in the Predicate Information of INDEX RANGE SCAN of the index (E.emp_id, E.emp_dept). But the (E.emp_dept, E.emp_id) composite index use INDEX SKIP SCAN without extra operation to filter the E.emp_dept again.

So, you have to test the order of composite index very carefully for correlated subqueries, sometimes it will give you improvements that exceed your expectation.

This kind of index recommendation can be achieved by Tosska SQL Tuning Expert for Oracle automatically.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2021-11-262022-03-16

How to use ORDERED Hint to Tune a SQL with subquery for Oracle?

Here the following is the description of the ORDERED hint.

The ORDERED hint causes Oracle to join tables in the order in which they appear in the FROM clause.

If you omit the ORDERED hint from a SQL statement performing a join, then the optimizer chooses the order in which to join the tables. You might want to use the ORDERED hint to specify a join order if you know something about the number of rows selected from each table that the optimizer does not. Such information lets you choose an inner and outer table better than the optimizer could.

We usually use an ORDERED hint to control the john order, but how this hint causes a SQL with a subquery. Let’s use the following SQL as an example to see how ORDERED hint works for a subquery.

SELECT *
FROM DEPARTMENT
where dpt_id
in (select emp_dept from employee
where emp_id >3300000)

Here the following is the query plan of the SQL, it takes 68.84 seconds to finish. The query shows a “TABLE ACCESS FULL” of the DEPARTMENT table and “NESTED LOOPS SEMI” to an “INDEX RANGE SCAN” of EMPLOYEE.

If you think it is not an effective plan, you may want to try to reorder the join path and see if an ORDERED hint is working or not in a subquery case like this:

SELECT /*+ ORDERED */ *
FROM department
WHERE dpt_id IN (SELECT emp_dept
FROM employee
WHERE emp_id > 3300000)

Here is the query plan of the hinted SQL and the speed is 3.44 seconds which is 20 times better than the original SQL. The new query plan shows the new join order that EMPLOYEE is retrieve first and then hash join DEPARTMENT later. You can see the ORDERED hint will order the subquery’s table first. This new order clauses a new data retrieval method from the EMPLOYEE table, it makes the overall performance much better than the original query plan.

This kind of rewrite can be achieved by Tosska SQL Tuning Expert for Oracle automatically, there are other hints-injection SQL with better performance, but it is not suitable to discuss in this short article, maybe I can discuss later in my blog.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2021-10-282021-10-28

How to tune a SQL that cannot be tuned ?

Some mission-critical SQL statements are already reached their maximum speed within the current indexes configuration. It means that those SQL statements are not able to be improved by syntax rewrite or Hints injection. Most people may think that the only way to improve this kind of SQL may be by upgrading hardware. For example, the following SQL statement has every column in WHERE clause is indexed and the best query plan is generated by Oracle already. There is no syntax rewrite or hints injection that can help Oracle to improve the SQL performance.

SELECT EMP_ID,
EMP_NAME,
SAL_EFFECT_DATE,
SAL_SALARY
FROM EMPLOYEE,
EMP_SAL_HIST,
DEPARTMENT,
GRADE
WHERE EMP_ID = SAL_EMP_ID
AND SAL_SALARY <200000
AND EMP_DEPT = DPT_ID
AND EMP_GRADE = GRD_ID
AND GRD_ID<1200 AND EMP_DEPT<‘D’

Here the following is the query plan and execution statistics of the SQL, it takes 2.33 seconds to extract all 502 records. It is not acceptable for a mission-critical SQL that is executed thousands of times in an hour. Do we have another choice if we don’t want to buy extra hardware to improve this SQL?

Introduce new plans for Oracle’s SQL optimizer to consider
Although all columns in the WHERE clause are indexed, can we build some compound indexes to help Oracle’s SQL optimizer to generate new query plans which may perform better than the original plan? Let’s see if we adopt the common practice that the following EMPLOYEE’s columns in red color can be used to compose a concatenated index (EMP_ID, EMP_DEPT, EMP_GRADE).

WHERE EMP_ID = SAL_EMP_ID
AND SAL_SALARY <200000
AND EMP_DEPT = DPT_ID
AND EMP_GRADE = GRD_ID
AND GRD_ID<1200
AND EMP_DEPT<‘D’

CREATE INDEX C##TOSSKA.TOSSKA_09145226686_V0043 ON C##TOSSKA.EMPLOYEE
(
EMP_ID,
EMP_DEPT,
EMP_GRADE
)

The following is the query plan after the concatenated index is created. Unfortunately, the speed of the SQL is 2.40 seconds although a new query plan is introduced by Oracle’s SQL optimizer.

To be honest, it is difficult if we just rely on common practices or human knowledge to build indexes to improve this SQL. Let me imagine that if we got an AI engine that can help me to try the most effective compound indexes to explore Oracle’s SQL optimizer potential solutions for the SQL. The following concatenated indexes are the potential recommendation by the imagined AI engine.

CREATE INDEX C##TOSSKA.TOSSKA_13124445731_V0012 ON C##TOSSKA.EMP_SAL_HIST
(
SAL_SALARY,
SAL_EFFECT_DATE,
SAL_EMP_ID
)
CREATE INDEX C##TOSSKA.TOSSKA_13124445784_V0044 ON C##TOSSKA.EMPLOYEE
(
EMP_GRADE,
EMP_DEPT,
EMP_ID,
EMP_NAME
)

The following is the query plan after these two concatenated indexes are created and the speed of the SQL is improved to 0.13 seconds. It is almost 18 times better than that of the original SQL without the new indexes.

The above indexes include some columns that appear on the SELECT list of the SQL and there is a correlated indexes relationship for Oracle’s SQL optimizer to generate the query plan, it means that missing any columns of the recommended indexes or reshuffling of the column position of the concatenated indexes may not be able to produce such query plan structure. So, it is difficult for a human expert to compose these two concatenated indexes manually. I am glad to tell you that this kind of AI engine is actually available in the following product.

https://www.tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2021-06-17

How to Tune SQL Statements to Run SLOWER… but Make Users Feel BETTER (Oracle)?

Your end-users may keep on complaining about some functions of their database application are running slow, but you may found that those SQL statements are already reached their maximum speed in the current Oracle and hardware configuration. There may be no way to improve the SQL unless you are willing to upgrade your hardware. To make your users feel better, sometimes, you don’t have to tune your SQL to run faster but to tune your SQL to run slower for certain application’s SQL statements.

This is an example SQL that is used to display the information from tables Emp_sal_hist and Employee if they are satisfied with certain criteria. This SQL is executed as an online query and users have to wait for at least 5 seconds before any data will be shown on screen after the mouse click.

select * from employee a,emp_sal_hist c
where a.emp_name like ‘A%’
and a.emp_id=c.sal_emp_id
and c.sal_salary<1800000
order by c.sal_emp_id

Here the following is the query plan and execution statistics of the SQL, it takes 10.41 seconds to extract all 79374 records and the first records return time ”Response Time” is 5.72 seconds. The query shows a MERGE JOIN of EMPLOYEE and EMP_SAL_HIST table, there are two sorting operations of the corresponding tables before it is being merged into the final result. It is the reason that users have to wait at least 5 seconds before they can see anything shows on the screen.

As the condition “a.emp_id = c.sal_emp_id”, we know that “ORDER BY c.sal_emp_id“ is the same as “ORDER BY a.emp_id“, as SQL syntax rewrite cannot force a specified operation in the query plan for this SQL, I added an optimizer hint /*+ INDEX(@SEL$1 A EMPLOYEE_PK) */ to reduce the sorting time of order by a.emp_id.

SELECT /*+ INDEX(@SEL$1 A EMPLOYEE_PK) */ *
FROM employee a,
emp_sal_hist c
WHERE a.emp_name LIKE ‘A%’
AND a.emp_id=c.sal_emp_id
AND c.sal_salary<1800000
ORDER BY c.sal_emp_id

Although the overall Elapsed Time is 3 seconds higher in the new query plan, the response time is now reduced from 5.72 seconds to 1.16 seconds, so the users can see the first page of information on the screen more promptly and I believe most users don’t care whether there are 3 more seconds for all 79374 records to be returned. That is why SQL tuning is an art rather than science when you are going to manage your users’ expectations.

This kind of rewrite can be achieved by Tosska SQL Tuning Expert for Oracle automatically.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2021-05-22

How to Tune SQL Statement with “< ANY (subquery)” Operator for Oracle?

Here the following is a simple SQL statement with a “< ANY (Subquery)” syntax.

SELECT *
FROM employee
WHERE emp_salary< ANY (SELECT emp_salary
FROM emp_subsidiary
where emp_dept=‘AAA’
)

Here the following is the query plan of the SQL, it takes 18.49 seconds to finish. The query shows a “TABLE ACCESS FULL” of EMPLOYEE table and “MERGE JOIN SEMI” to a VIEW that is composed of a HASH JOIN of two indexes “INDEX RANGE SCAN” of EMP_SUBSIDIARY.

You can see that it is not an efficient query plan if we know that the emp_salary of EMP_SUBSIDIARY is a not null column, we can rewrite the SQL into the following syntax. The Nvl(Max(emp_salary),-99E124)is going to handle the case that if the subquery returns no record, the -99E124 representing the minimum number that the emp_salary can store to force an unconditional true for the subquery comparison.

SELECT *
FROM employee
WHERE emp_salary < (SELECT Nvl(Max(emp_salary),-99E124)
FROM emp_subsidiary
WHERE emp_dept = ‘AAA’)

Here is the query plan of the rewritten SQL and the speed is 0.01 seconds which is 1800 times better than the original syntax. The new query plan shows an “INDEX RANGE SCAN” instead of “TABLE ACCESS FULL” of EMPLOYEE.

This kind of rewrite can be achieved by Tosska SQL Tuning Expert for Oracle automatically, there are other rewrites with similar performance, but it is not suitable to discuss in this short article, maybe I can discuss later in my blog.

https://tosska.com/tosska-sql-tuning-expert-pro-tse-pro-for-oracle/

2021-05-212023-02-18

Optimization in SQL: Answering 4 Commonly-Asked Questions

A SQL query or statement is tasked with fetching the required information from the database. While the same output can be gained from different statements, they are likely to work at different performance levels.

The difference in performance output makes a lot of difference because a millisecond of lapse in query execution can result in huge losses for the organization. This makes it extremely necessary to ensure the best statement is being used, which is where optimization in SQL is considered.

#1: What is Query Optimization in Databases?

Query optimization in databases is the general process of picking out the most efficient way of obtaining data from the database i.e. carrying out the best query for a given requirement. Since SQL is nonprocedural, it can be processed, merged, and reorganized as seen fit by the optimizer and the database.

The database enhances each query on the basis of various statistics gathered about the information fetched from it. On the other hand, the optimizer selects the optimal plan for a query after assessing different access techniques including index and full-table scans. Various join methods and orders are also used along with certain probable transformations.

#2: What is Query Cost in Optimization?

Query cost is a metric that helps examine execution plans and determine the optimal one. Depending on the SQL statement and the environment, the optimizer sets an estimated numerical cost for every step throughout potential plans and considers an aggregate to derive the overall cost estimate for it.

The total query cost of a query is the sum of the costs incurred at every step in it. Since query cost is a comparative estimate of the resources needed to carry out every step of an execution plan, it doesn’t have any unit. The optimizer picks out the plan with the least cost projection once it has completed all its calculations of all the available plans.

#3: Is Query Cost the Best Way to Judge Performance?

In a word: No. Why? Although query cost proves useful in comprehending the manner in which a specific query is optimized, we must bear in mind its main goal: helping the optimizer select decent execution plans.

It does not offer a direct measure of parameters such as CPU, IO, memory, duration that are significant to users waiting for a statement to finish running. In other words, a low query cost won’t necessarily mean the plan is optimal or the query in question is the quickest. Similarly, a high query cost can prove more efficient in comparison, which is why it is not recommended to depend too much on query cost when considering performance.

Being a CPU-intensive operation query optimization in SQL takes a lot of resources to determine the best plan among the ones present. Time also needs to be factored in here as the user may not always have the time it may take for this entire process to take place.

Therefore, the resources required to optimize a statement, those required to run the statement, and the time it takes for all of this to be done with shouldn’t exceed each other.

#4: How Can We Optimize a SQL Query?

Query optimization often needs extra resources, such as the addition of indexes. However, we can boost query performance by simply rewriting a statement to decrease resource consumption without further expenses.

This lets us save significant resources, money, and time (if a query optimization tool is used). Through query optimization in SQL, we can focus on specific areas that are causing latency instead of examining the entire procedure. In such cases, looking for sections that are taking up more resources will help us narrow down the search and fix issues more quickly.